What is the solution for x^2y^{''}-xy^'+y=0,y=x ?

The solution for x^2y^{''}-xy^'+y=0,y=x is y=c_{1}x+c_{2}ln(x)x

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x^2y^{''}-xy^'+y=0,y=x

x^{2} y^{^{''}} - x y^{^{'}} + y = 0, y (0) = x

y = c_{1} x + c_{2} ln (x) x

Solution steps

x^{2} y^{''} (x) - x y^{'} (x) + y = 0

Solve linear ODE:

y = c_{1} x + c_{2} ln (x) x

y = c_{1} x + c_{2} ln (x) x

What is the solution for x^2y^{''}-xy^'+y=0,y=x ?
The solution for x^2y^{''}-xy^'+y=0,y=x is y=c_{1}x+c_{2}ln(x)x