What is the tangent of f(x)=(x^2)/(x-3),\at x=0 ?

The tangent of f(x)=(x^2)/(x-3),\at x=0 is y=0

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tangent of f(x)=(x^2)/(x-3),\at x=0

tangent of

f (x) = \frac{x ^{2}}{x - 3}, at x = 0

y = 0

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = \frac{x ^{2}}{x - 3} : \frac{df ( x )}{d x} = \frac{x ^{2} - 6 x}{( x - 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(0, 0) : y = 0

y = 0

What is the tangent of f(x)=(x^2)/(x-3),\at x=0 ?
The tangent of f(x)=(x^2)/(x-3),\at x=0 is y=0