What is the tangent of f(x)= 1/(x^2),\at x=-1 ?

The tangent of f(x)= 1/(x^2),\at x=-1 is y=2x+3

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tangent of f(x)= 1/(x^2),\at x=-1

tangent of

f (x) = \frac{1}{x ^{2}}, at x = - 1

y = 2 x + 3

Solution steps

Find the tangent point:

(- 1, 1)

Find the slope of

f (x) = \frac{1}{x ^{2}} : \frac{df ( x )}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(- 1, 1) : y = 2 x + 3

y = 2 x + 3

What is the tangent of f(x)= 1/(x^2),\at x=-1 ?
The tangent of f(x)= 1/(x^2),\at x=-1 is y=2x+3