What is the derivative of 3x^2+1/(x^3) ?

The derivative of 3x^2+1/(x^3) is 6x-3/(x^4)

What is the first derivative of 3x^2+1/(x^3) ?

The first derivative of 3x^2+1/(x^3) is 6x-3/(x^4)

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\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

6 x - \frac{3}{x ^{4}}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{1}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{1}{x ^{3}})

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{1}{x ^{3}}) = - \frac{3}{x ^{4}}

= 6 x - \frac{3}{x ^{4}}

What is the derivative of 3x^2+1/(x^3) ?
The derivative of 3x^2+1/(x^3) is 6x-3/(x^4)
What is the first derivative of 3x^2+1/(x^3) ?
The first derivative of 3x^2+1/(x^3) is 6x-3/(x^4)