What is the tangent of f(x)=4+x-2x^2-3x^3,\at x=2 ?

The tangent of f(x)=4+x-2x^2-3x^3,\at x=2 is y=-43x+60

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tangent of f(x)=4+x-2x^2-3x^3,\at x=2

tangent of

f (x) = 4 + x - 2 x^{2} - 3 x^{3}, at x = 2

y = - 43 x + 60

Solution steps

Find the tangent point:

(2, - 26)

Find the slope of

f (x) = 4 + x - 2 x^{2} - 3 x^{3} : \frac{df ( x )}{d x} = - 9 x^{2} - 4 x + 1

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 43

Find the line with slope m=

- 43

and passing through

(2, - 26) : y = - 43 x + 60

y = - 43 x + 60

What is the tangent of f(x)=4+x-2x^2-3x^3,\at x=2 ?
The tangent of f(x)=4+x-2x^2-3x^3,\at x=2 is y=-43x+60