What is the derivative of 2^x+cos(3x) ?

The derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3

What is the first derivative of 2^x+cos(3x) ?

The first derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3

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\frac{d}{d x} (2^{x} + cos (3 x))

2^{x} ln (2) - sin (3 x) \cdot 3

Solution steps

\frac{d}{d x} (2^{x} + cos (3 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2^{x}) + \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (2^{x}) = 2^{x} ln (2)

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= 2^{x} ln (2) - sin (3 x) \cdot 3

What is the derivative of 2^x+cos(3x) ?
The derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3
What is the first derivative of 2^x+cos(3x) ?
The first derivative of 2^x+cos(3x) is 2^xln(2)-sin(3x)*3