What is the tangent of f(x)=2x^2-9x+10,\at x=1 ?

The tangent of f(x)=2x^2-9x+10,\at x=1 is y=-5x+8

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tangent of f(x)=2x^2-9x+10,\at x=1

tangent of

f (x) = 2 x^{2} - 9 x + 10, at x = 1

y = - 5 x + 8

Solution steps

Find the tangent point:

(1, 3)

Find the slope of

f (x) = 2 x^{2} - 9 x + 10 : \frac{df ( x )}{d x} = 4 x - 9

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 5

Find the line with slope m=

- 5

and passing through

(1, 3) : y = - 5 x + 8

y = - 5 x + 8

What is the tangent of f(x)=2x^2-9x+10,\at x=1 ?
The tangent of f(x)=2x^2-9x+10,\at x=1 is y=-5x+8