What is the derivative of-6x^{1/4} ?

The derivative of-6x^{1/4} is -3/(2x^{3/4)}

What is the first derivative of-6x^{1/4} ?

The first derivative of-6x^{1/4} is -3/(2x^{3/4)}

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\frac{d}{d x} (- 6 x^{\frac{1}{4}})

- \frac{3}{2 x ^{\frac{3}{4}}}

Solution steps

\frac{d}{d x} (- 6 x^{\frac{1}{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 6 \frac{d}{d x} (x^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 6 \cdot \frac{1}{4} x^{\frac{1}{4} - 1}

Simplify

- 6 \cdot \frac{1}{4} x^{\frac{1}{4} - 1} : - \frac{3}{2 x ^{\frac{3}{4}}}

= - \frac{3}{2 x ^{\frac{3}{4}}}

What is the derivative of-6x^{1/4} ?
The derivative of-6x^{1/4} is -3/(2x^{3/4)}
What is the first derivative of-6x^{1/4} ?
The first derivative of-6x^{1/4} is -3/(2x^{3/4)}