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Popular Calculus >

integral of 1/(3+y)

Solution

\int \frac{1}{3 + y} d y

Solution

ln ∣ 3 + y ∣ + C

Solution steps

\int \frac{1}{3 + y} d y

Apply u-substitution

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 3 + y

= ln ∣ 3 + y ∣

Add a constant to the solution

= ln ∣ 3 + y ∣ + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1/(3+y) ?
The integral of 1/(3+y) is ln|3+y|+C