What is the first derivative of 2+e^x ?

The first derivative of 2+e^x is e^x

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derivative of 2+e^x

\frac{d}{d x} (2 + e^{x})

e^{x}

Solution steps

\frac{d}{d x} (2 + e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (e^{x})

\frac{d}{d x} (2) = 0

\frac{d}{d x} (e^{x}) = e^{x}

= 0 + e^{x}

Simplify

= e^{x}