What is the solution for y^'sin(x)+ycos(x)=0,y(pi/4)=1 ?

The solution for y^'sin(x)+ycos(x)=0,y(pi/4)=1 is y= 1/(sqrt(2)sin(x))

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y^'sin(x)+ycos(x)=0,y(pi/4)=1

y^{^{'}} sin (x) + y cos (x) = 0, y (\frac{π}{4}) = 1

y = \frac{1}{2 sin ( x )}

Solution steps

y^{'} (x) sin (x) + y cos (x) = 0

Solve separable ODE:

y = \frac{1}{2 sin ( x )}

y = \frac{1}{2 sin ( x )}

What is the solution for y^'sin(x)+ycos(x)=0,y(pi/4)=1 ?
The solution for y^'sin(x)+ycos(x)=0,y(pi/4)=1 is y= 1/(sqrt(2)sin(x))