What is the tangent of f(x)=sqrt(3x+7),(3,4) ?

The tangent of f(x)=sqrt(3x+7),(3,4) is y= 3/8 x+23/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=sqrt(3x+7),(3,4)

tangent of

f (x) = 3 x + 7, (3, 4)

y = \frac{3}{8} x + \frac{23}{8}

Solution steps

Find the slope of

f (x) = 3 x + 7 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 7}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{8}

Find the line with slope m=

\frac{3}{8}

and passing through

(3, 4) : y = \frac{3}{8} x + \frac{23}{8}

y = \frac{3}{8} x + \frac{23}{8}

What is the tangent of f(x)=sqrt(3x+7),(3,4) ?
The tangent of f(x)=sqrt(3x+7),(3,4) is y= 3/8 x+23/8