What is area y=2x^3+3x^2-4x,y=x^2 ?

The answer to area y=2x^3+3x^2-4x,y=x^2 is 37/6

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area y=2x^3+3x^2-4x,y=x^2

area

y = 2 x^{3} + 3 x^{2} - 4 x, y = x^{2}

\frac{37}{6}

Decimal

6.16666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{1} 2 x^{3} + 2 x^{2} - 4 x d x

Solve

\int_{- 2}^{1} 2 x^{3} + 2 x^{2} - 4 x d x : \frac{37}{6}

The area is:

= \frac{37}{6}

What is area y=2x^3+3x^2-4x,y=x^2 ?
The answer to area y=2x^3+3x^2-4x,y=x^2 is 37/6