What is area y=x^2,y= 2/((x^2+1)) ?

The answer to area y=x^2,y= 2/((x^2+1)) is -2/3+pi

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area y=x^2,y= 2/((x^2+1))

area

y = x^{2}, y = \frac{2}{( x ^{2} + 1 )}

- \frac{2}{3} + π

Decimal

2.47492 \dots

Solution steps

Apply the area formula:

\int_{- 1}^{1} x^{2} - \frac{2}{x ^{2} + 1} d x

Solve

\int_{- 1}^{1} x^{2} - \frac{2}{x ^{2} + 1} d x : - \frac{2}{3} + π

The area is:

= - \frac{2}{3} + π

What is area y=x^2,y= 2/((x^2+1)) ?
The answer to area y=x^2,y= 2/((x^2+1)) is -2/3+pi