(x^2+2x)^'

Lösung

(x^{2} + 2 x)^{^{'}}

2 x + 2

Schritte zur Lösung

(x^{2} + 2 x)^{'}

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{2})^{^{'}} + (2 x)^{^{'}}

(x^{2})^{'} = 2 x

(2 x)^{'} = 2

= 2 x + 2

x \to 1 + lim (\frac{5}{x ^{3} - 1})

\int \frac{x + 5}{x ^{2} + 10 x} d x

\int_{0}^{1} π (1 - x^{2}) d x

in v erse l a pl a ce \frac{- 5}{s ( s ^{2} - 5 s + 4 )}

d er i v a t i v e y = - 3 x - 2