What is the integral of 3/(x^{3/4)}-4\sqrt[3]{x}+1 ?

The integral of 3/(x^{3/4)}-4\sqrt[3]{x}+1 is 12\sqrt[4]{x}-3x^{4/3}+x+C

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integral of 3/(x^{3/4)}-4\sqrt[3]{x}+1

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int \frac{3}{x ^{\frac{3}{4}}} d x = 12 x^{\frac{1}{4}}

\int 1 d x = x

= 12 x^{\frac{1}{4}} - 3 x^{\frac{4}{3}} + x

Apply radical rule:

Add a constant to the solution

What is the integral of 3/(x^{3/4)}-4\sqrt[3]{x}+1 ?
The integral of 3/(x^{3/4)}-4\sqrt[3]{x}+1 is 12\sqrt[4]{x}-3x^{4/3}+x+C