What is the solution for y^'-((2x)/(1+x^2))y=1 ?

The solution for y^'-((2x)/(1+x^2))y=1 is y=arctan(x)(1+x^2)+c_{1}(1+x^2)

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y^'-((2x)/(1+x^2))y=1

y^{^{'}} - (\frac{2 x}{1 + x ^{2}}) y = 1

y = arctan (x) (1 + x^{2}) + c_{1} (1 + x^{2})

Solution steps

y^{'} (x) - (\frac{2 x}{1 + x ^{2}}) y = 1

Solve linear ODE:

y = arctan (x) (1 + x^{2}) + c_{1} (1 + x^{2})

y = arctan (x) (1 + x^{2}) + c_{1} (1 + x^{2})

What is the solution for y^'-((2x)/(1+x^2))y=1 ?
The solution for y^'-((2x)/(1+x^2))y=1 is y=arctan(x)(1+x^2)+c_{1}(1+x^2)