What is the solution for (5t+2y+6)dt-dy=0 ?

The solution for (5t+2y+6)dt-dy=0 is y=-(5t)/2-17/4+c_{1}e^{2t}

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(5t+2y+6)dt-dy=0

(5 t + 2 y + 6) d t - d y = 0

y = - \frac{5 t}{2} - \frac{17}{4} + c_{1} e^{2 t}

Solution steps

(5 t + 2 y + 6) d t - d y = 0

Solve linear ODE:

y = - \frac{5 t}{2} - \frac{17}{4} + c_{1} e^{2 t}

y = - \frac{5 t}{2} - \frac{17}{4} + c_{1} e^{2 t}

What is the solution for (5t+2y+6)dt-dy=0 ?
The solution for (5t+2y+6)dt-dy=0 is y=-(5t)/2-17/4+c_{1}e^{2t}