What is the limit as x approaches 1 of (ln(x))^{1-x} ?

The limit as x approaches 1 of (ln(x))^{1-x} is Does not exist

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limit as x approaches 1 of (ln(x))^{1-x}

x \to 1 lim ((ln (x))^{1 - x})

Does not exist

Solution steps

x \to 1 lim ((ln (x))^{1 - x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 1 + lim ((ln (x))^{1 - x}) = 1

x \to 1 - lim ((ln (x))^{1 - x}) =

Does not exist

= Does not exist

What is the limit as x approaches 1 of (ln(x))^{1-x} ?
The limit as x approaches 1 of (ln(x))^{1-x} is Does not exist