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Popular Calculus >

y^'=a^{x+y}

Solution

y^{^{'}} = a^{x + y}

Solution

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

Solution steps

y^{'} (x) = a^{x + y}

Solve separable ODE:

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

y = - \frac{ln ( - a ^{x} - c _{1} ln ( a ) )}{ln ( a )}

Popular Examples

integral of x/(sqrt(x-x^2))

derivative of 6ln(4x)

(dy)/(dx)=85yx^{16}

sum from n=0 to infinity of 2*(2/5)^n

Frequently Asked Questions (FAQ)

What is the solution for y^'=a^{x+y} ?
The solution for y^'=a^{x+y} is y=-(ln(-a^x-c_{1}ln(a)))/(ln(a))