derivative of sec(8x^3+1)

解答

\frac{d}{d x} (sec (8 x^{3} + 1))

sec (8 x^{3} + 1) tan (8 x^{3} + 1) \cdot 24 x^{2}

求解步骤

\frac{d}{d x} (sec (8 x^{3} + 1))

使用连锁律:

sec (8 x^{3} + 1) tan (8 x^{3} + 1) \frac{d}{d x} (8 x^{3} + 1)

= sec (8 x^{3} + 1) tan (8 x^{3} + 1) \frac{d}{d x} (8 x^{3} + 1)

\frac{d}{d x} (8 x^{3} + 1) = 24 x^{2}

= sec (8 x^{3} + 1) tan (8 x^{3} + 1) \cdot 24 x^{2}

t an g e n t f (x) = 18 x, at x = 9

\int_{0}^{2} \frac{1}{x ^{2} - 4} d x

\frac{d}{d x} ((2 + x)^{- 3})

\int e^{- s t} t^{3} d t

x \to 0 + lim (cos^{\frac{1}{x}} (x))