What is the first derivative of x^2+64 ?

The first derivative of x^2+64 is 2x

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derivative of x^2+64

derivative of

x^{2} + 64

2 x

Solution steps

\frac{d}{d x} (x^{2} + 64)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (64)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (64) = 0

= 2 x + 0

Simplify

= 2 x