What is the integral of (3x^2-6x-7) ?

The integral of (3x^2-6x-7) is x^3-3x^2-7x+C

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integral of (3x^2-6x-7)

\int (3 x^{2} - 6 x - 7) d x

x^{3} - 3 x^{2} - 7 x + C

Solution steps

\int 3 x^{2} - 6 x - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 6 x d x - \int 7 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 7 d x = 7 x

= x^{3} - 3 x^{2} - 7 x

Add a constant to the solution

= x^{3} - 3 x^{2} - 7 x + C

What is the integral of (3x^2-6x-7) ?
The integral of (3x^2-6x-7) is x^3-3x^2-7x+C