What is the integral of x+1/(sqrt(x))-7 ?

The integral of x+1/(sqrt(x))-7 is (x^2)/2+2sqrt(x)-7x+C

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integral of x+1/(sqrt(x))-7

\int x + \frac{1}{x} - 7 d x

\frac{x ^{2}}{2} + 2 x - 7 x + C

Solution steps

\int x + \frac{1}{x} - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int \frac{1}{x} d x - \int 7 d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{1}{x} d x = 2 x

\int 7 d x = 7 x

= \frac{x ^{2}}{2} + 2 x - 7 x

Add a constant to the solution

= \frac{x ^{2}}{2} + 2 x - 7 x + C

What is the integral of x+1/(sqrt(x))-7 ?
The integral of x+1/(sqrt(x))-7 is (x^2)/2+2sqrt(x)-7x+C