integral of (9x^2-8x+4)

Lösung

\int (9 x^{2} - 8 x + 4) d x

3 x^{3} - 4 x^{2} + 4 x + C

Schritte zur Lösung

\int 9 x^{2} - 8 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 9 x^{2} d x - \int 8 x d x + \int 4 d x

\int 9 x^{2} d x = 3 x^{3}

\int 8 x d x = 4 x^{2}

\int 4 d x = 4 x

= 3 x^{3} - 4 x^{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= 3 x^{3} - 4 x^{2} + 4 x + C

n = 1 \sum \infty 8 (\frac{1}{5})^{n}

\frac{d}{d x} ((5 x)^{7 x})

x \to 0 + lim (\frac{5 x}{sin ( x )})

x \to 3 - lim (- x^{2} + \frac{5}{2} x + 3)

\frac{d}{d x} (\frac{5 x ^{6} + 4 x ^{5} + 3 x ^{4}}{6 x ^{2}})