What is (\partial)/(\partial z)(x*cos(y)*sin(z)) ?

The answer to (\partial)/(\partial z)(x*cos(y)*sin(z)) is xcos(y)cos(z)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial z)(xcos(y)sin(z))

\frac{\partial}{\partial z} (x \cdot cos (y) \cdot sin (z))

x cos (y) cos (z)

Solution steps

\frac{\partial}{\partial z} (x cos (y) sin (z))

Treat

x, y

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x cos (y) \frac{\partial}{\partial z} (sin (z))

Apply the common derivative:

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= x cos (y) cos (z)

What is (\partial)/(\partial z)(x*cos(y)*sin(z)) ?
The answer to (\partial)/(\partial z)(x*cos(y)*sin(z)) is xcos(y)cos(z)