derivative of (4x/(x^2+4))

Lösung

\frac{d}{d x} (\frac{4 x}{x ^{2} + 4})

\frac{4 ( - x ^{2} + 4 )}{( x ^{2} + 4 ) ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{4 x}{x ^{2} + 4})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x ^{2} + 4})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 4 ) - \frac{d}{d x} ( x ^{2} + 4 ) x}{( x ^{2} + 4 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 4) = 2 x

= 4 \cdot \frac{1 \cdot ( x ^{2} + 4 ) - 2 xx}{( x ^{2} + 4 ) ^{2}}

Vereinfache

4 \cdot \frac{1 \cdot ( x ^{2} + 4 ) - 2 xx}{( x ^{2} + 4 ) ^{2}} : \frac{4 ( - x ^{2} + 4 )}{( x ^{2} + 4 ) ^{2}}

= \frac{4 ( - x ^{2} + 4 )}{( x ^{2} + 4 ) ^{2}}

\int \frac{x ^{3}}{9 - x ^{2}} d x

\frac{\partial}{\partial y} (4 x^{2} + y^{2})

\frac{\partial}{\partial y} (8 - 2 x^{2} + y^{2})

d er i v a t i v e f (x) = x^{2} (x^{2} + 1)

\frac{\partial}{\partial y} (x e^{- x^{2} - y^{2}})