derivative f(x)=(x^3)/3+4x^2+12x+19

Lösung

ableitung von

f (x) = \frac{x ^{3}}{3} + 4 x^{2} + 12 x + 19

x^{2} + 8 x + 12

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} + 4 x^{2} + 12 x + 19)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (12 x) + \frac{d}{d x} (19)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (19) = 0

= x^{2} + 8 x + 12 + 0

Vereinfache

= x^{2} + 8 x + 12

e^{x} (y - 1) d x + 2 (e^{x} + 4) d y = 0

d er i v a t i v e \frac{3}{x ^{4} + 7 x + 1}

x \to 1 lim ([2 f (x) + g (x)])

t an g e n t y = (\frac{( x + 2 )}{( x - 2 ) ^{2}})

\int \frac{- 1}{( x - 1 ) ^{2}} d x