What is the tangent of f(x)=-3/(x^2-4),(1,1) ?

The tangent of f(x)=-3/(x^2-4),(1,1) is y= 2/3 x+1/3

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tangent of f(x)=-3/(x^2-4),(1,1)

tangent of

f (x) = - \frac{3}{x ^{2} - 4}, (1, 1)

y = \frac{2}{3} x + \frac{1}{3}

Solution steps

Find the slope of

f (x) = - \frac{3}{x ^{2} - 4} : \frac{df ( x )}{d x} = \frac{6 x}{( x ^{2} - 4 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{2}{3}

Find the line with slope m=

\frac{2}{3}

and passing through

(1, 1) : y = \frac{2}{3} x + \frac{1}{3}

y = \frac{2}{3} x + \frac{1}{3}

What is the tangent of f(x)=-3/(x^2-4),(1,1) ?
The tangent of f(x)=-3/(x^2-4),(1,1) is y= 2/3 x+1/3