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Popular Calculus >

x^2y^'-ysqrt(x)=0

Solution

x^{2} y^{^{'}} - y x = 0

Solution

y = e^{- \frac{2}{x} + c_{1}}

Solution steps

x^{2} y^{'} (x) - y x = 0

Solve separable ODE:

y = e^{- \frac{2}{x} + c_{1}}

y = e^{- \frac{2}{x} + c_{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-ysqrt(x)=0 ?
The solution for x^2y^'-ysqrt(x)=0 is y=e^{-2/(sqrt(x))+c_{1}}