What is the tangent of y=x^3-3x^2+2,(3,2) ?

The tangent of y=x^3-3x^2+2,(3,2) is y=9x-25

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tangent of y=x^3-3x^2+2,(3,2)

tangent of

y = x^{3} - 3 x^{2} + 2, (3, 2)

y = 9 x - 25

Solution steps

Find the slope of

y = x^{3} - 3 x^{2} + 2 : \frac{d y}{d x} = 3 x^{2} - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9

Find the line with slope m=

9

and passing through

(3, 2) : y = 9 x - 25

y = 9 x - 25

What is the tangent of y=x^3-3x^2+2,(3,2) ?
The tangent of y=x^3-3x^2+2,(3,2) is y=9x-25