What is the derivative of 120x^3-240x^2+120x ?

The derivative of 120x^3-240x^2+120x is 360x^2-480x+120

What is the first derivative of 120x^3-240x^2+120x ?

The first derivative of 120x^3-240x^2+120x is 360x^2-480x+120

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\frac{d}{d x} (120 x^{3} - 240 x^{2} + 120 x)

360 x^{2} - 480 x + 120

Solution steps

\frac{d}{d x} (120 x^{3} - 240 x^{2} + 120 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (120 x^{3}) - \frac{d}{d x} (240 x^{2}) + \frac{d}{d x} (120 x)

\frac{d}{d x} (120 x^{3}) = 360 x^{2}

\frac{d}{d x} (240 x^{2}) = 480 x

\frac{d}{d x} (120 x) = 120

= 360 x^{2} - 480 x + 120

What is the derivative of 120x^3-240x^2+120x ?
The derivative of 120x^3-240x^2+120x is 360x^2-480x+120
What is the first derivative of 120x^3-240x^2+120x ?
The first derivative of 120x^3-240x^2+120x is 360x^2-480x+120