What is the integral of e^{x^2+1}2x ?

The integral of e^{x^2+1}2x is e^{x^2+1}+C

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integral of e^{x^2+1}2x

\int e^{x^{2} + 1} 2 x d x

e^{x^{2} + 1} + C

Solution steps

\int e^{x^{2} + 1} \cdot 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{x^{2} + 1} x d x

Apply u-substitution

= 2 \cdot \int \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 2 \cdot \frac{1}{2} e^{u}

Substitute back

u = x^{2} + 1

= 2 \cdot \frac{1}{2} e^{x^{2} + 1}

Simplify

2 \cdot \frac{1}{2} e^{x^{2} + 1} : e^{x^{2} + 1}

= e^{x^{2} + 1}

Add a constant to the solution

= e^{x^{2} + 1} + C

What is the integral of e^{x^2+1}2x ?
The integral of e^{x^2+1}2x is e^{x^2+1}+C