What is the solution for y^'=xy^3 ?

The solution for y^'=xy^3 is y=sqrt(-1/(x^2+c_{1))},y=-sqrt(-1/(x^2+c_{1))}

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y^'=xy^3

y^{^{'}} = x y^{3}

y = - \frac{1}{x ^{2} + c _{1}}, y = - - \frac{1}{x ^{2} + c _{1}}

Solution steps

y^{'} (x) = x y^{3}

Solve separable ODE:

y = - \frac{1}{x ^{2} + c _{1}}, y = - - \frac{1}{x ^{2} + c _{1}}

y = - \frac{1}{x ^{2} + c _{1}}, y = - - \frac{1}{x ^{2} + c _{1}}

What is the solution for y^'=xy^3 ?
The solution for y^'=xy^3 is y=sqrt(-1/(x^2+c_{1))},y=-sqrt(-1/(x^2+c_{1))}