What is the solution for yy^'= 7/x ?

The solution for yy^'= 7/x is y=sqrt(14ln(x)+c_{1)},y=-sqrt(14ln(x)+c_{1)}

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yy^'= 7/x

y y^{^{'}} = \frac{7}{x}

y = 14 ln (x) + c_{1}, y = - 14 ln (x) + c_{1}

Solution steps

y y^{'} (x) = \frac{7}{x}

Solve separable ODE:

y = 14 ln (x) + c_{1}, y = - 14 ln (x) + c_{1}

y = 14 ln (x) + c_{1}, y = - 14 ln (x) + c_{1}

What is the solution for yy^'= 7/x ?
The solution for yy^'= 7/x is y=sqrt(14ln(x)+c_{1)},y=-sqrt(14ln(x)+c_{1)}