What is the tangent of y= 2/(1+x^2),(2,0.4) ?

The tangent of y= 2/(1+x^2),(2,0.4) is y=-8/25 x+1.04

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tangent of y= 2/(1+x^2),(2,0.4)

tangent of

y = \frac{2}{1 + x ^{2}}, (2, 0.4)

y = - \frac{8}{25} x + 1.04

Solution steps

Find the slope of

y = \frac{2}{1 + x ^{2}} : \frac{d y}{d x} = - \frac{4 x}{( 1 + x ^{2} ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{8}{25}

Find the line with slope m=

- \frac{8}{25}

and passing through

(2, 0.4) : y = - \frac{8}{25} x + 1.04

y = - \frac{8}{25} x + 1.04

What is the tangent of y= 2/(1+x^2),(2,0.4) ?
The tangent of y= 2/(1+x^2),(2,0.4) is y=-8/25 x+1.04