What is the derivative of y=x^2sin(4x) ?

The derivative of y=x^2sin(4x) is 2xsin(4x)+cos(4x)*4x^2

What is the first derivative of y=x^2sin(4x) ?

The first derivative of y=x^2sin(4x) is 2xsin(4x)+cos(4x)*4x^2

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derivative of

y = x^{2} sin (4 x)

2 x sin (4 x) + cos (4 x) \cdot 4 x^{2}

Solution steps

\frac{d}{d x} (x^{2} sin (4 x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (4 x)

= \frac{d}{d x} (x^{2}) sin (4 x) + \frac{d}{d x} (sin (4 x)) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (4 x)) = cos (4 x) \cdot 4

= 2 x sin (4 x) + cos (4 x) \cdot 4 x^{2}

What is the derivative of y=x^2sin(4x) ?
The derivative of y=x^2sin(4x) is 2xsin(4x)+cos(4x)*4x^2
What is the first derivative of y=x^2sin(4x) ?
The first derivative of y=x^2sin(4x) is 2xsin(4x)+cos(4x)*4x^2