What is the solution for yy^'+xy^2=xy^4 ?

The solution for yy^'+xy^2=xy^4 is y=sqrt(1/(e^{x^2-c_{1))+1}},y=-sqrt(1/(e^{x^2-c_{1))+1}}

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yy^'+xy^2=xy^4

y y^{^{'}} + x y^{2} = x y^{4}

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

Solution steps

y y^{'} (x) + x y^{2} = x y^{4}

Solve Bernoulli ODE:

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

y = \frac{1}{e ^{x^{2} - c_{1}} + 1}, y = - \frac{1}{e ^{x^{2} - c_{1}} + 1}

What is the solution for yy^'+xy^2=xy^4 ?
The solution for yy^'+xy^2=xy^4 is y=sqrt(1/(e^{x^2-c_{1))+1}},y=-sqrt(1/(e^{x^2-c_{1))+1}}