What is laplacetransform 5sin(t) ?

The answer to laplacetransform 5sin(t) is 5/(s^2+1)

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laplacetransform 5sin(t)

laplace transform

5 sin (t)

\frac{5}{s ^{2} + 1}

Solution steps

L {5 sin (t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {sin (t)}

L {sin (t)} : \frac{1}{s ^{2} + 1}

= 5 \cdot \frac{1}{s ^{2} + 1}

Refine

5 \frac{1}{s ^{2} + 1} : \frac{5}{s ^{2} + 1}

= \frac{5}{s ^{2} + 1}

What is laplacetransform 5sin(t) ?
The answer to laplacetransform 5sin(t) is 5/(s^2+1)