What is the tangent of f(x)=x^3+2x,\at x=0 ?

The tangent of f(x)=x^3+2x,\at x=0 is y=2x

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tangent of f(x)=x^3+2x,\at x=0

tangent of

f (x) = x^{3} + 2 x, at x = 0

y = 2 x

Solution steps

Find the tangent point:

(0, 0)

Find the slope of

f (x) = x^{3} + 2 x : \frac{df ( x )}{d x} = 3 x^{2} + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(0, 0) : y = 2 x

y = 2 x

What is the tangent of f(x)=x^3+2x,\at x=0 ?
The tangent of f(x)=x^3+2x,\at x=0 is y=2x