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Popular Calculus >

y^'(t)=(y+1)*(y-3),y(0)=1

Solution

y^{^{'}} (t) = (y + 1) \cdot (y - 3), y (0) = 1

Solution

y^{2} - 2 y - 3

Solution steps

Find

(y + 1) \cdot (y - 3)

given

y (0) = 1

(y + 1) \cdot (y - 3) = (y + 1) \cdot (y - 3)

y : 1

y : 1

= (y + 1) (y - 3)

Expand

(y + 1) (y - 3) : y^{2} - 2 y - 3

= y^{2} - 2 y - 3

Graph

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Frequently Asked Questions (FAQ)

What is the y^'(t)=(y+1)*(y-3),y(0)=1 ?
The y^'(t)=(y+1)*(y-3),y(0)=1 is y^2-2y-3