What is the solution for y^'=2ty(1-y) ?

The solution for y^'=2ty(1-y) is y=-(e^{t^2+c_{1}})/(1-e^{t^2+c_{1)}}

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y^'=2ty(1-y)

y^{^{'}} = 2 t y (1 - y)

y = - \frac{e ^{t^{2} + c_{1}}}{1 - e ^{t^{2} + c_{1}}}

Solution steps

y^{'} (t) = 2 t y (1 - y)

Solve separable ODE:

y = - \frac{e ^{t^{2} + c_{1}}}{1 - e ^{t^{2} + c_{1}}}

y = - \frac{e ^{t^{2} + c_{1}}}{1 - e ^{t^{2} + c_{1}}}

What is the solution for y^'=2ty(1-y) ?
The solution for y^'=2ty(1-y) is y=-(e^{t^2+c_{1}})/(1-e^{t^2+c_{1)}}