What is the derivative of g(x)=(x^2-16)/(x-4) ?

The derivative of g(x)=(x^2-16)/(x-4) is 1

What is the first derivative of g(x)=(x^2-16)/(x-4) ?

The first derivative of g(x)=(x^2-16)/(x-4) is 1

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derivative of

g (x) = \frac{x ^{2} - 16}{x - 4}

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 16}{x - 4})

Simplify

\frac{x ^{2} - 16}{x - 4} : x + 4

= \frac{d}{d x} (x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (4)

\frac{d x}{d x} = 1

\frac{d}{d x} (4) = 0

= 1 + 0

Simplify

= 1

What is the derivative of g(x)=(x^2-16)/(x-4) ?
The derivative of g(x)=(x^2-16)/(x-4) is 1
What is the first derivative of g(x)=(x^2-16)/(x-4) ?
The first derivative of g(x)=(x^2-16)/(x-4) is 1