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Popular Calculus >

integral of yz^2

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Solution

∫yz2dy

Solution

2z2y2​+C
Solution steps
∫yz2dy
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=z2⋅∫ydy
Apply the Power Rule
=z22y2​
Multiply fractions: a⋅cb​=ca⋅b​=2z2y2​
Add a constant to the solution=2z2y2​+C

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Popular Examples

integral of (4+e^x)integral of (e^{3x})/(9+e^{2x)}integral from 0 to sqrt(3 of)(6/(1+x^2))limit as x approaches 0 of (3x-4)^4derivative of 2sqrt(e^{(sin(w))/3)+1}

Frequently Asked Questions (FAQ)

  • What is the integral of yz^2 ?

    The integral of yz^2 is (z^2y^2)/2+C
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