y^{''}-2y^'+26y=e^xsin(x)

Lösung

y^{^{''}} - 2 y^{^{'}} + 26 y = e^{x} sin (x)

y = e^{x} (c_{1} cos (5 x) + c_{2} sin (5 x)) + \frac{1}{24} e^{x} sin (x)

Schritte zur Lösung

y^{''} (x) - 2 y^{'} (x) + 26 y = e^{x} sin (x)

Solve linear ODE:

y = e^{x} (c_{1} cos (5 x) + c_{2} sin (5 x)) + \frac{1}{24} e^{x} sin (x)

y = e^{x} (c_{1} cos (5 x) + c_{2} sin (5 x)) + \frac{1}{24} e^{x} sin (x)

\frac{\partial}{\partial x} (e^{2 x + 8 y})

t an g e n t 8 x

\frac{\partial}{\partial x} (2 y^{3})

d er i v a t i v e (5 x - 3)^{4} (2 x - 7)^{- 3}

\frac{d}{d x} (\frac{3 x ^{2}}{x})