What is (\partial)/(\partial x)(3x^2-2xy+x-3y) ?

The answer to (\partial)/(\partial x)(3x^2-2xy+x-3y) is 6x+1-2y

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(\partial)/(\partial x)(3x^2-2xy+x-3y)

\frac{\partial}{\partial x} (3 x^{2} - 2 x y + x - 3 y)

6 x + 1 - 2 y

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 2 x y + x - 3 y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (3 y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (3 y) = 0

= 6 x - 2 y + 1 - 0

Simplify

= 6 x + 1 - 2 y

What is (\partial)/(\partial x)(3x^2-2xy+x-3y) ?
The answer to (\partial)/(\partial x)(3x^2-2xy+x-3y) is 6x+1-2y