(\partial)/(\partial x)(3x^2-2xy+x-3y)

Lösung

\frac{\partial}{\partial x} (3 x^{2} - 2 x y + x - 3 y)

6 x + 1 - 2 y

Schritte zur Lösung

\frac{\partial}{\partial x} (3 x^{2} - 2 x y + x - 3 y)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (2 x y) + \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (3 y)

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 x y) = 2 y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (3 y) = 0

= 6 x - 2 y + 1 - 0

Vereinfache

= 6 x + 1 - 2 y

n = 0 \sum \infty \frac{1}{n ^{2} + 3}

x \to 1 lim (- x^{2})

\frac{d}{d x} (\frac{2}{2 - x})

\int \frac{( x ^{2} )}{x ^{2} + 1} d x

\frac{d}{d x} (5 - 2 (x - 2)^{2})