What is (\partial)/(\partial t)(cos(t)-sin(t)) ?

The answer to (\partial)/(\partial t)(cos(t)-sin(t)) is -sin(t)-cos(t)

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(\partial)/(\partial t)(cos(t)-sin(t))

\frac{\partial}{\partial t} (cos (t) - sin (t))

- sin (t) - cos (t)

Solution steps

\frac{\partial}{\partial t} (cos (t) - sin (t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (cos (t)) - \frac{\partial}{\partial t} (sin (t))

\frac{\partial}{\partial t} (cos (t)) = - sin (t)

\frac{\partial}{\partial t} (sin (t)) = cos (t)

= - sin (t) - cos (t)

What is (\partial)/(\partial t)(cos(t)-sin(t)) ?
The answer to (\partial)/(\partial t)(cos(t)-sin(t)) is -sin(t)-cos(t)