What is the derivative of f(x)=(3x^2+1)^3 ?

The derivative of f(x)=(3x^2+1)^3 is 18x(3x^2+1)^2

What is the first derivative of f(x)=(3x^2+1)^3 ?

The first derivative of f(x)=(3x^2+1)^3 is 18x(3x^2+1)^2

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derivative of

f (x) = (3 x^{2} + 1)^{3}

18 x (3 x^{2} + 1)^{2}

Solution steps

\frac{d}{d x} ((3 x^{2} + 1)^{3})

Apply the chain rule:

3 (3 x^{2} + 1)^{2} \frac{d}{d x} (3 x^{2} + 1)

= 3 (3 x^{2} + 1)^{2} \frac{d}{d x} (3 x^{2} + 1)

\frac{d}{d x} (3 x^{2} + 1) = 6 x

= 3 (3 x^{2} + 1)^{2} \cdot 6 x

Simplify

= 18 x (3 x^{2} + 1)^{2}

What is the derivative of f(x)=(3x^2+1)^3 ?
The derivative of f(x)=(3x^2+1)^3 is 18x(3x^2+1)^2
What is the first derivative of f(x)=(3x^2+1)^3 ?
The first derivative of f(x)=(3x^2+1)^3 is 18x(3x^2+1)^2