What is the solution for y^'+2y=e^{-2t} ?

The solution for y^'+2y=e^{-2t} is y= t/(e^{2t)}+(c_{1})/(e^{2t)}

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y^'+2y=e^{-2t}

y^{^{'}} + 2 y = e^{- 2 t}

y = \frac{t}{e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

Solution steps

y^{'} (t) + 2 y = e^{- 2 t}

Solve linear ODE:

y = \frac{t}{e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

y = \frac{t}{e ^{2 t}} + \frac{c _{1}}{e ^{2 t}}

What is the solution for y^'+2y=e^{-2t} ?
The solution for y^'+2y=e^{-2t} is y= t/(e^{2t)}+(c_{1})/(e^{2t)}