What is (\partial)/(\partial x)(1+3x^2y^2) ?

The answer to (\partial)/(\partial x)(1+3x^2y^2) is 6xy^2

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(\partial)/(\partial x)(1+3x^2y^2)

\frac{\partial}{\partial x} (1 + 3 x^{2} y^{2})

6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (1 + 3 x^{2} y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (3 x^{2} y^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (3 x^{2} y^{2}) = 6 y^{2} x

= 0 + 6 y^{2} x

Simplify

= 6 x y^{2}

What is (\partial)/(\partial x)(1+3x^2y^2) ?
The answer to (\partial)/(\partial x)(1+3x^2y^2) is 6xy^2